Unit 9: Applications of Thermodynamics
๐ฌ Real-World Chemistry Examples (with Numbers)
Example 1: Electrochemical Cell – Calculate ฮG from E°
Given:
Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)
E°cell = +1.10 V
n = 2 mol e⁻
F = 96,485 C/mol
Solution:
ฮG° = –nFE° = –(2)(96,485)(1.10) = –212,267 J = –212.3 kJ
✅ This means the reaction is spontaneous under standard conditions.
Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)
E°cell = +1.10 V
n = 2 mol e⁻
F = 96,485 C/mol
Solution:
ฮG° = –nFE° = –(2)(96,485)(1.10) = –212,267 J = –212.3 kJ
✅ This means the reaction is spontaneous under standard conditions.
Example 2: Predict Spontaneity Using ฮH and ฮS
Given:
ฮH = –92.0 kJ/mol
ฮS = –198 J/mol·K
T = 298 K
Convert: ฮS = –0.198 kJ/mol·K
ฮG = ฮH – TฮS = –92.0 – (298)(–0.198) = –92.0 + 59.0 = –33.0 kJ/mol
✅ Spontaneous at room temperature.
ฮH = –92.0 kJ/mol
ฮS = –198 J/mol·K
T = 298 K
Convert: ฮS = –0.198 kJ/mol·K
ฮG = ฮH – TฮS = –92.0 – (298)(–0.198) = –92.0 + 59.0 = –33.0 kJ/mol
✅ Spontaneous at room temperature.
Example 3: Using ฮG to Estimate K
Given: ฮG° = –34.2 kJ/mol, T = 298 K, R = 8.314 J/mol·K
Convert ฮG: –34,200 J
ln K = –ฮG / RT = 34200 / (8.314 × 298) ≈ 13.8
K ≈ e13.8 ≈ ~9.8 × 10⁵
✅ Product-favored reaction.
Convert ฮG: –34,200 J
ln K = –ฮG / RT = 34200 / (8.314 × 298) ≈ 13.8
K ≈ e13.8 ≈ ~9.8 × 10⁵
✅ Product-favored reaction.
Example 4: Entropy Change in a Reaction
Reaction: N₂(g) + 3H₂(g) → 2NH₃(g)
ฮS° = ฮฃS°(products) – ฮฃS°(reactants)
= [2 × 193] – [1 × 191 + 3 × 131] = 386 – 584 = –198 J/mol·K
❗ Even though ฮS is negative, this reaction is still spontaneous because ฮH is very negative (exothermic).
ฮS° = ฮฃS°(products) – ฮฃS°(reactants)
= [2 × 193] – [1 × 191 + 3 × 131] = 386 – 584 = –198 J/mol·K
❗ Even though ฮS is negative, this reaction is still spontaneous because ฮH is very negative (exothermic).
Example 5: ATP Hydrolysis in Biology
ATP → ADP + Pi
ฮG° = –30.5 kJ/mol (biochemical standard conditions)
๐ This energy is used to power non-spontaneous reactions like protein synthesis or muscle contraction by reaction coupling.
ฮG° = –30.5 kJ/mol (biochemical standard conditions)
๐ This energy is used to power non-spontaneous reactions like protein synthesis or muscle contraction by reaction coupling.
Takeaway:
- Thermodynamics is everywhere: batteries, metabolism, chemical production
- Practice reading values, converting units, and interpreting signs
- Expect math-based MCQs and verbal FRQs based on these concepts
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