๐ Shortcut: Count regions of electron density around the central atom:
2 → sp | 3 → sp2 | 4 → sp3 | 5 → sp3d | 6 → sp3d2
2 → sp | 3 → sp2 | 4 → sp3 | 5 → sp3d | 6 → sp3d2
๐ง Count bonds + lone pairs = regions of density. That gives hybridization AND geometry!
๐ Hybridization & Shape Pairings
- sp → linear → 180°
- sp2 → trigonal planar → 120°
- sp3 → tetrahedral → 109.5°
- sp3d → trigonal bipyramidal → 90°, 120°
- sp3d2 → octahedral → 90°
๐ง Quick Question
What is the hybridization of the central atom in CO2?
⚡ Lone Pairs Matter
Include lone pairs in the count! 3 bonds + 1 lone pair = 4 regions = sp3 → Geometry may be bent or trigonal pyramidal.
๐ Real Example
What is the geometry of NH3 based on its hybridization?
No comments:
Post a Comment